Question

In triangle PR²=PQ²+QR³ then what is the value of angle PQR
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Answer 1

Answer:

$\sf\frac{PQ}{QR} = \sqrt[]{\frac{5}{2} }$

• Step-by-step explanation:

• ⇝Given PQR is an isoceles triangle (PQ=PR). Also given that RS and QT are medians to the Sides PQ and PR respectively.

• ⇝The condition is that the medians intersect each other at right angles

• ⇝According the theorem when medians intersect each other at 90° in an isosceles triangle

⇝$\sf PQ^{2} +PR^{2} = 5 QR^{2}$

• Now PQ= PR

• ⇝2PQ^2= 5QR^2

THUS, PQR =

⇝ $\sf\frac{PQ}{QR} = \sqrt[]{\frac{5}{2} }$