Question

in triangle right angled at b, if Tan A= 1/√3 Find value of Sin A Cos C.

Give answer​

Answer 1

Step-by-step explanation:

tan A = 1/√3

therefore BC/AB=1/√3

therefore AB=√3BC......(1)

now in traingle ABC AC is hypo.

therefore AC^2=AB^2+BC^2

AC^2=(√3BC)^2+BC^2

AC^2=3+1BC^2=4BC^2

AC=2BC,BC/AC=1/2....(2)

SinA=BC/AC and CosC=BC/AC

therefore SinA*CosC=1/2*1/2=1/4

therefore 1/4 answer

Hope it helps........