Question

in triangle right angled at b, if Tan A= 1/√3 Find value of Sin A Cos C.

Answer it pls Fast guys​

Answer 1

if tan = 1/√3

, then (AC) = 1 , (BC) = √3

by applying Pythagora's theorem in the right angled triangle ABC we get,

(AC)^2 = (AB)^2+ (BC)^2

1 = (AB)^2 + 3

or,AB = - ✓2

now, Sin A = AC/BC

sinA = 1/✓3 ans.....

again, cos C = AB/BC

cosC= -✓2 / ✓ 3 is Ur answer..

plz mark me as brainliest...

Answer 2

Answer:

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