Question

In triangle side AB Equals to side BC, IF angle A is 70 degree find Angle C?​

Answer 1

Answer:

∠ACB=50

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Sum of angles =180

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Let ∠BCD=x,∠BDC=y

now, x+y=60

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[exterior angle property]

Also, 70+50+x+y=180

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Sum of angles =180

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for triangle ACD

Given BD=BC ⇒x=y=30

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Two sides of same length hence same angle.

∠ACD=50

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+30

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=80

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Now, in ΔACD,CD is the side opposite to ∠A & AD is side opposite to ∠C.

∵∠C>∠A

∴AD>CD[∵ side opposite to greater angle is longer ]

Answer 2

We're given that in triangle ABC, AB = BC, so it is an isosceles triangle.

And, if two Sides of a traingle are equal then their opposite angles are also equal

So Angle A = Angle C = 70°

Hope this Helped! ヾ(•ω•`)o