In triangle side BC of a triangle ABC has been produced to a point D. If angle ACD=115° and angle A=45°,then angle B is what?
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Step-by-step explanation:
angle A is 45°
angle ACD is 115°
angle ACD + angle ACB = 180° ( ACD is straight lin)
115°+ angle ACB = 180°
angle ACB =180°-115°
angle ACB = 65°
In ∆ ABC,
angle A + angle B + angle C =180°
45°+angle B+65°=180°
angle B +110°=180°
angle B=180°-110°
angle B=70°
thanks....
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Answer is in picture....❤️
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