In triangle , the line BO and CO bisect the angle B=70 and angle C =60 respectively find the angle BOC
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hey mate
Step-by-step explanation:
In triangle ABC
Using Angle Sum Property, angleA + angleB + angleC = 180
Since angleA = 70, angleB + angleC = 110 →(i)
In triangle BOC
Using Angle Sum Property, angleBOC + angleOCB + angleOBC = 180
angleBOC + 1/2angleC + 1/2angleB = 180
angleBOC + 1/2(angleC + angleB) = 180
angleBOC + 1/2(110) = 180
angleBOC = 180-55
angleBOC = 125
Alter method: Using Corrolary of Angle Sum Property
angleBOC = 90 + 1/2angleA
angleBOC = 90 + 35
angleBOC = 125
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