in triangle xyz A and B are points on the side xy and xz respectively such that AB parallel to YZ .if AY=2.2 XB=3.3 and XZ=6.6 and then find AX
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in ∆XYZ using B.P.T.
we get
we get
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AX = 2.2
Step-by-step explanation:
Given that,
AY = 2.2 cm
XB = 3.3 cm
XZ = 6.6
Since XB = 3.3 cm,
BZ = XZ - XB
BZ = 6.6 - 3.3
∵ BZ = 3.3 cm
AB ║ YZ
Now,
by using B.P.T., we will find AX:
∵ AY/AX = BZ/BX
⇒ 2.2/AX = 3.3/3.3
∵ AX = 2.2 cm
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