In triangle XYZ, angle X are 20 degree more than angle Y. If angle Z = 38 degree, find the angle for X and Y.
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let angle X be 'a'
ATQ
angle Y=28+a
GIVEN ANGLE Z = 38 DEGREE
SO BY ANGLE SUM PROPERTY
ANGLE X + ANGLE Y + ANGLE Z = 180 DEGREE
therefore a+20+a+38=180
2a + 58 = 180
2a = 180-58
2a = 122
a = 61
therefoe angle X = 61 and angle Y = 81
hope its right
ATQ
angle Y=28+a
GIVEN ANGLE Z = 38 DEGREE
SO BY ANGLE SUM PROPERTY
ANGLE X + ANGLE Y + ANGLE Z = 180 DEGREE
therefore a+20+a+38=180
2a + 58 = 180
2a = 180-58
2a = 122
a = 61
therefoe angle X = 61 and angle Y = 81
hope its right
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