Question

in triangle xyz angle x is equal to 64 degree angle xyz equal to 52 degree if yo and zo are bisectors of angle xyz and angle xyz respectively of triangle xyz intersect at 0 then (1) draw figure (2) find angle ozy (3) find angle yoz​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

As the sum of all interior angles of a triangle is 180º, therefore, for ΔXYZ,

∠X + ∠XYZ + ∠XZY = 180º

62º + 54º + ∠XZY = 180º

∠XZY = 180º − 116º

∠XZY = 64º

∠OZY = 32º (OZ is the angle bisector of ∠XZY)

Similarly, ∠OYZ == 27º

Using angle sum property for ΔOYZ, we obtain

∠OYZ + ∠YOZ + ∠OZY = 180º

27º + ∠YOZ + 32º = 180º

∠YOZ = 180º − 59º

∠YOZ = 121º

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