In triangle XYZ exterior ∠ = 110°, ∠ = 2° and ∠ = 3°. Find x.
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Answer:
In ∆XYZ we have,
→ ∠X = 70°
→ ∠Z = 40°
So,
→ ∠X + ∠Y + ∠Z = 180° { By angle sum property. }
then,
→ 70° + ∠Y + 40° = 180°
→ ∠Y + 110° = 180°
→ ∠Y = 180° - 110°
→ ∠Y = 70°
now,
→ ∠XYZ + ∠XYW = 180° { Linear pair. }
→ 70° + ∠XYW = 180°
→ ∠XYW = 180° - 70°
→ ∠XYW = 110° (Ans.)
Method (2) :-
→ ∠XYW = ∠YXZ + ∠YZX { Exterior angle is equal to sum of opposite interior angles. }
→ ∠XYW = 70° + 40°
→ ∠XYW = 110° (Ans.)
Step-by-step explanation:
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