in triangle XYZ <XYZ=90* XP=PZ,XY=14CM YZ=8.5CM find the area of triangle XYP
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Answered by
15
area of triangle = 1/2 base × height
so....1/2×14×8.5
7×8.5
59.5
so....1/2×14×8.5
7×8.5
59.5
Narendra931:
Area of tringle xyz = 1/2×base× height then area of xyz = 1/2×14×8.5=59.5 and area of xyp = 1/2 area of xyz then area of xyp = 1/2× 59.5= 29.7
Answered by
6
Answer: 57.33 cm²
Step-by-step explanation:
Since, in the right triangle XYZ,
∠ XYZ = 90°, XY=14 cm YZ=8.5 cm,
Thus, by the Pythagoras theorem,
(XZ)² = (XY)² + (YZ)²
⇒ (XZ)² = 14² + 8.5² = 196 + 72.25 = 268.25
⇒ XZ = 16.3783394 cm ≈ 16.38 cm,
Hence, the area of the triangle XYZ,
= 1/2 × XY × XZ
= 1/2 × 14 × 16.38 = 7 × 16.38 = 114.66 cm²
Since, P is the mid point of the side AX ( Because, XP=PZ ),
Thus, YP is the median of the triangle XYZ,
By the property of the median,
Area of the triangle XYP = 1/2 of the area of the triangle XYZ
= 1/2 of 114.66
= 57.33 cm²
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