Question

in triangle xyz, p is any point on xy and pq is perpendicular to xz. if xp =4cm, xy =16cm and xz=24cm, find xq

Answer 1

hope it will help you

Answer 2

XQ = 2.67 cm if P is any point on xy and PQ is perpendicular to XZand xp = 4 cm,x y = 16 cm and xz = 24 cm

Step-by-step explanation:

Comparing triangle XQP & XYZ

∠X = ∠X  ( common angle)

∠XQP = ∠XYZ

=>  XQP ≈ XYZ

=> XQ/XY  = QP/YZ  = XP/XZ

=>  XQ/16  = 4/24

=> XQ = 16 /6

=> XQ = 8/3

=> XQ = 2.67 cm

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