Question

In triangle XYZ, right angle is at Y, YZ=x and XZ=2x then determine angle YXZ and angle YXZ

Answer 1

There is a mistake in the question. Angle YXZ and angle YZX are be found.
The student has mentioned angle YXZ and angle YXZ but it wrong. I have tried my best to solve it.
Solution:-
Sin x = opposite side of x/hypotenuse
⇒ x/2x = 1/2
Sin x = 1/2 = Sin 30°
⇒ x = 30° or ∠ YXZ = 30°
Cos Z = Adjacent side of z/hypotenuse
⇒ x/2x = 1/2 
⇒ Cos Z = 1/2 = Cos 60°
Z = 60° = ∠ YZX = 60°  Answer.

Answer 2

Answer :

THERE IS A MISTAKE IN THE QUESTION THAT   we have determine angle YXZ and angle YZX so lets get started.

Solution :

               we know that COS Z =  $\frac{adjacent side}{hypotenuse}$ =  $\frac{x}{2x}$ = $\frac{1}{2}$

                                       COS Z = COS 60

                                                   = $\frac{1}{2}$  

                                        therefore, angle YXZ = 30

                                                          angle YZX = 60