Question

In triangle XYZ, the measure of angle X is 30° greater than the measure of angle Y and angle Z is a right angle. The measure of ∠X and ∠Y respectively is

Please answer the question with step by step explanation and the correct answer will be marked as the brainliest.

Answer 1

Answer:

In ΔXYZ, the measure of ∠X is 30° greater than the measure of ∠Y and ∠Z is a right angle. Find measure of ∠Y.

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Step-by-step explanation:

Measure of ∠X = ∠Y + 30° Measure of ∠Z = 90° We know that, the sum of all three angles in a triangle is equal to 180° Read more on Sarthaks.com - https://www.sarthaks.com/793367/in-xyz-the-measure-is-30-greater-than-the-measure-of-y-and-z-is-right-angle-find-measure-of?show=793372#a793372

Answer 2

$\bf{According \: to \: question }$

$\sf{ \angle X = 30 ^{ \circ} + \angle Y}$

$\sf{ \angle Z = {90}^{ \circ} }$

$\bf{Also,}$

$\sf{ \angle X + \angle Y + \angle Z = {180}^{ \circ} }$

$\sf{ (\angle Y + {30}^{ \circ} ) + \angle Y + {90}^{ \circ} = {180}^{ \circ} }$

$\sf{ 2\angle Y + {120}^{ \circ} = {180}^{ \circ} }$

$\sf{ 2\angle Y = {180}^{ \circ} - {120}^{ \circ} }$

$\sf{{ 2\angle Y = {60}^{ \circ}}}$

$\sf{ \pink{ \angle Y = {30}^{ \circ}}}$

$\sf \pink{ \angle X = 3 {0}^{ \circ} + 3 {0}^{ \circ} = 6 {0}^{ \circ} }$