Question

In triangle XYZ, XY=4 cm , YZ = 6 cm, XZ = 5 cm If triangle XYZ is triangle PQR and P Q = 8 cm, then find the length of remaining sides of triangle PQR.​

Answer 1

Answer:

answer

the length of reaming sides of triangle PQR

pq+qr+pr=15

8+qr+pr=15

qr+pr=15-8

qr+pr=7

qr and pr = 3.5 cm

Answer 2

Answer:

Xy/pq = yz/qr = xz/pr(corresponding sides of triangles)

4/8 = 6/qr = 5/pr

4/8 = 6/qr

QR = 6×8/4

QR= 48/4

QR= 12 cm

Similarly,

4/8 = 5/pr

PR= 5×8/4

PR=40/10

PR= 10 cm

Hence sides are

PQ=8 cm

QR = 12cm

PR=10cm