in triangle xyz xy is greater than xz and P is any point on the side y z prove that x y is greater than XP
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xy > xp , In triangle xyz xy greater than xz p is any point on side yz
Step-by-step explanation:
xy > xz
as angle opposite to larger side is greater
=> ∠z > ∠y
∠ypx = ∠p
∠ypx = ∠pxz + ∠z
=> ∠p > ∠z
∠z > ∠y
=> ∠p > ∠z > ∠y
=> ∠p > ∠y
in Δxyp
∠p > ∠y
=> xy > xp
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