IN TRIANGLE XYZ, XY = XZ. A STRAIGHT LINE CUTS XZ AT P, YZ AT Q AND XY PROUCED AT R. IF YQ=YR AND QP=QZ.FIND ANGLES OF THE TRIANGLE XYZ
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There is a mistake in the question. Angle YXZ and angle YZX are be found.
The student has mentioned angle YXZ and angle YXZ but it wrong. I have tried my best to solve it.
Solution:-
Sin x = opposite side of x/hypotenuse
⇒ x/2x = 1/2
Sin x = 1/2 = Sin 30°
⇒ x = 30° or ∠ YXZ = 30°
Cos Z = Adjacent side of z/hypotenuse
⇒ x/2x = 1/2
⇒ Cos Z = 1/2 = Cos 60°
Z = 60° = ∠ YZX = 60° Answer.
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