Question

In triangle XYZ, XY= XZ. A straight line cuts XZ at P, YZ at Q and XY produced at R. If YQ=YR and QP=QZ find the angles of triangle XYZ.

Plz answer......
It's urgent..........
Hull explanation plz.....​

Answer 1

Step-by-step explanation:

There is a mistake in the question. Angle YXZ and angle YZX are be found.

and angle YZX are be found.The student has mentioned angle YXZ and angle YXZ but it wrong. I have tried my best to solve it.

Solution:-

Sin x = opposite side of x/hypotenuse

⇒ x/2x = 1/2

Sin x = 1/2 = Sin 30°

⇒ x = 30° or ∠ YXZ = 30°

Cos Z = Adjacent side of z/hypotenuse

Cos Z = Adjacent side of z/hypotenuse⇒ x/2x = 1/2 

⇒ Cos Z = 1/2 = Cos 60°

Z = 60° = ∠ YZX = 60°  Answer.

Answer 2

Step-by-step explanation:

Sin x = opposite of x/hypotenuse

⇒ x/2x = 1/2

Sin x = 1/2 = Sin 30°

⇒ x = 30° or ∠ YXZ = 30°

Cos Z = Adjacent of z/hypotenuse

⇒ x/2x = 1/2

⇒ Cos Z = 1/2 = Cos 60°

Z = 60° or ∠ YZX = 60°

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