In triangle XYZ, XY= XZ. A straight line cuts XZ at P, YZ at Q and XY produced at R. If YQ=YR and QP=QZ find the angles of triangle XYZ.
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Step-by-step explanation:
Step-by-step explanation:
There is a mistake in the question. Angle YXZ and angle YZX are be found.
and angle YZX are be found.The student has mentioned angle YXZ and angle YXZ but it wrong. I have tried my best to solve it.
Solution:-
Sin x = opposite side of x/hypotenuse
⇒ x/2x = 1/2
Sin x = 1/2 = Sin 30°
⇒ x = 30° or ∠ YXZ = 30°
Cos Z = Adjacent side of z/hypotenuse
Cos Z = Adjacent side of z/hypotenuse⇒ x/2x = 1/2
⇒ Cos Z = 1/2 = Cos 60°
Z = 60° = ∠ YZX = 60° Answer.
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