Question

in triangle XYZ, XY=YZ and, YM is the median, show that triangle YMX is congruent triangle YMZ step by step explanation​

Answer 1

Answer:

[tex]\boxed{

\begin{minipage}{7 cm}

Fundamental Trigonometric Identities \\ \\

$\sin^2\theta + \cos^2\theta=1 \\ \\

1+\tan^2\theta = \sec^2\theta \\ \\

1+\cot^2\theta = \text{cosec}^2 \, \theta$

\end{minipage}

}[/tex]

Answer 2

Step-by-step explanation:

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