In triangleABC,AB=5,BC=6,AC=7.TrianglePQR is similar to triangleABC.Perimeter of trianglePQR is 360.Find PQ,QR and PR.
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Ans=Given, △ABC∼△PQR, as corresponding sides of similar triangles are proportional,
∴
PQ
AB
=
QR
BC
=
RP
CA
=
k
1
(let)
Also, AB=5,BC=6,AC=7 So, PQ=5k,QR=6k,RP=7k
Perimeter of △PQR=PQ+QR+RP
⇒360=5k+6k+7k⇒360=18k⇒k=20
Thus, PQ=5×20=100,QR=6×20=120,RP=7×20=140
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