In triangleABC AB=AC and angle B is 2/5 of angle A Find the measure of angle A
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Step-by-step explanation:
It is given that ∠A+∠B=125
∘
…(1)
We know that the sum of all the angles in a triangle is 180
∘
.
So we can write it as
∠A+∠B+∠C=180
∘
By substituting ∠A+∠B=125
∘
in the above equation
125
∘
+∠C=180
∘
On further calculation
∠C=180
∘
−125
∘
By subtraction
∠C=55
∘
It is given that ∠A+∠C=113
∘
By substituting the value of ∠C
∠A+55
∘
=113
∘
On further calculation
∠A=113
∘
−55
∘
By subtraction
∠A=58
∘
By substituting ∠A=58
∘
in equation (1)
So we get
∠A+∠B=125
∘
58
∘
+∠B=125
∘
On further calculation
∠B=125
∘
−58
∘
By subtraction
∠B=67
∘
Therefore, ∠A=58
∘
,∠B=67
∘
and ∠C=55
∘
.
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