Math, asked by sahilsuman93323, 1 month ago

In triangleABC, Ab = root 10 , Ac = root 2 , BE=EC = root5 divide by 2 and angle D =90,A,E,D are coilener ratio of area of triangle ABC to the area of triangle ABD in its lowest terms p/q.find the value of p-q .​

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Answered by wwwshammasmdnr786
1

Answer:

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Step-by-step explanation:

AC length=2√10. tanb=2. tanc=3. ATQ,. tanc=>p/b=AB/BC=3. AB/BC=3. AB=3BC . By pythogorous theorm:-. AB²+BC²=AC² ...

Answered by rosoni28
12

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  • answer is P=10,Q=7

STEP BY STEP EXPLANATIONS

Let think the two numbers are X and y

The difference between them is 3

So,we can write, x-y=3

The difference between their Squares is 51

So,we can write, X^2 - y^2 =51

Let, X^2 -y^2=51

or, (X+y)(x-y)=51

or,(X+y) 3 =51

(x+y)=17

(x−y)=3

2x=20

x=10

(X+y)=17

y=17-10=7

therefore,X=10,y=7(Answer)

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