Question

In triangleABC,AD perpendicular BC.find the length of Bc. Given that AB=13cm,AD=12cm,Ac=15Cm ​

Answer 1

Step-by-step explanation:

this is your answer please mark me brainlist

Answer 2

ANSWER:

The length side of BC = 14 cm.

STEP BY STEP EXPLANATION:

∆ABD:-

Let the length of side BD be x.

By using Pythagoras Theorem,

${(ab)}^{2} = {(ad)}^{2} + {( bd)}^{2}$

${(13)}^{2} = {(12)}^{2} + {(x)}^{2}$

$169 = 144 + {x}^{2}$

$169 - 144 = {x}^{2}$

$25 = {x}^{2}$

$\sqrt{25} = x = 5cm$

∆ACD:-

Let the length of side DC be y.

By using Pythagoras Theorem,

$(ac)^{2} =(ad)^{2} +(dc)^{2}$

$(15)^{2} =(12)^{2} +(y)^{2}$

$225 = 144 +y^{2}$

$225-144=y^{2}$

$81=y^{2}$

$\sqrt{81} =y=9cm$

Since, BC = BD + DC

                = 5cm + 9cm

                = 14cm.

Hope this answer will helpful for you!!

If you really like this answer, please mark this answer as Brainliest

ThankYou..