In triangleABC and triangleDEF, AB = FD and angleA= angleD, the two triangle will be congruent
by SAS test if.
(A) BC = EF (B)AC = DE
(C) AC=EF (D)BC = DE
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Answer:
For triangle to be congruent by SAS axiom two of the sides and the included angle of the triangles must be equal.
Given AB=DF and ∠A=∠D
No for △ABC≅△DFE by SAS axiom we need AC=DE
So option B is correct.
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