in triangleABC angle A=90degree then cos(B+C)=
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the sum of three angles of a triangle is 180degree. if A=90 then B+C=90
we know that cos90°=0 ans
we know that cos90°=0 ans
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Hiii,
cosB = B/h = Ab/BC
cosC = B/h = Ac/BC
Ab+Ac/BC = cos(B+C)
Hope it may help U
plzzz mark as brainliest.
cosB = B/h = Ab/BC
cosC = B/h = Ac/BC
Ab+Ac/BC = cos(B+C)
Hope it may help U
plzzz mark as brainliest.
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