Question

. In triangleABC, angleA = 80° and angleB = 60°. If triangleABC ~ triangleRQP, find the value of angleP​

Answer 1

Answer:

I hope it helps you.

Step-by-step explanation:

In ∆ ABC,

angleA = 80° and angleB = 60°

Now, angleA + angleB + angleC = 180°

(angle sum property of a ∆)

=> 80° + 60° + angleC = 180°

=> 140°+ angleC = 180°

=> angleC = 180°- 140°

=> angleC = 40°

As ∆ABC is congruent to ∆RQP.

Therefore, angleA = angleR = 80°

angleB = angleQ = 60°

angleC = angleP = 40°

Hence, angleP = 40°

Answer 2

Answer:

Above answer is correct. ........N verified. ....