In triangleABC, angleA+angleB=65°,angleB+angleC=140° find the value of angleB and C
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Since,A+B=65°
C=180°-65°=115°
B+C=140°
B+115°=140°
B=25°
Therefore,
A+B+C=180°
A+140°=180°
A=40°.
Hope it helps.
Please mark it as brainliest.
C=180°-65°=115°
B+C=140°
B+115°=140°
B=25°
Therefore,
A+B+C=180°
A+140°=180°
A=40°.
Hope it helps.
Please mark it as brainliest.
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