Question

In triangleABC, angleA+angleB=65°,angleB+angleC=140° find the value of angleB and C

Answer 1

Since,A+B=65°
C=180°-65°=115°

B+C=140°
B+115°=140°
B=25°

Therefore,
A+B+C=180°
A+140°=180°
A=40°.


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