Math, asked by 8956666060, 4 months ago

In triangleABC, angleABC =90°. Write the ratio of

tan (90-theta)​

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Answered by StudiousBookworm
0

Answer:

i. Sin(90-theeta)=cos theeta

cos theeta = b/h=4/5

ii. tan(90-theeta) = cot theeta

cot theeta = b/p = 4/3

Step-by-step explanation:

by complimentary angles in trigonometry

i.Sin(90-theeta)=cos theeta

ii.tan(90-theeta)=cot theeta

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