Question

In triangleABC, angleB =90 °and D is the midpoint of BC. Prove that}{BC ^2-4(AD^2AB^2)}

Answer 1

Answer:

In right ABC, using Pythagoras theorem, we have:

AC2 = AB2 + BC2 ...(1)

In right ABD, using Pythagoras theorem, we have:

AD2 = AB2 + BD2



BC2 = 4AD2 - 4AB2 ...(2)

Substituting (2) in (1), we get,

AC2 = 4AD2 - 3AB2

Hence, proved.

Hope it helps!!

Answer 2

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