Question

In triangleABC ,B=50°,C=62° then find A=?​

Answer 1

Answer:

$\huge\tt{Given} \:$

$\mathcal{In \: triangle \: ABC} \:$

$\mathcal{B=50° } \:$

$\mathcal{C= 62°} \:$

$\huge\tt{To \: find : }$

$\mathcal{A= \: ?} \:$

$\huge\mathfrak\red{Solving} \:$

∆A + ∆B + ∆C = 180°

∆A + 50° + 62° = 180°

∆A + 112° = 180°

∆A = 180° - 112°

∆A = 68°

_______________________________

Sum property of triangle is 180°

Step-by-step explanation:

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Answer 2

The correct answer is angle A is 68° in ΔABC.

Given:

ΔABC in which angle B is 50° and angle C is 62°

To find:

Angle A

Solution:

According to triangle rules, the total of the three angles formed by the triangle's three sides equals 180°.

suggests that

Angle B + Angle C + Angle A = 180°

Let's say that angle A is x° right now.

implies that angle A + angle B + angle C = 180°.

⇒62°+50°+x°=180°

⇒112°+x°=180°

⇒x°=180°-112°

⇒x°=68°

The value of x suggests that angle A has a value of 68°.

After confirming the response,

Angle A + Angle B + Angle C = 180°

=68+62+50=180°

We can see that the discovered solution satisfies the requirement, hence angle A is equal to 68°.

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