Question

in triangleAbc, Bc = 5 cm and area is 10 cm square what is the perpendicular distance from A to the side BC? ​

Answer 1

A) Let us consider a perpendicular AD.

Area = 10cm^2

10cm^2 =I/2 * BC * AD

20cm^2 = 5cm * AD

AD = 4cm

Therefore the perpendicular distance between A and BC is 4cm.

B) infinite as long as both the height and base are constant.

Answer 2

Step-by-step explanation:

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