In triangleABC, BC=AB and angle B=80°,then angle A is equal to
I need a step by step explailation.
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Step-by-step explanation:
BC=AB
⇒∠A=∠C (As angles opposite to equal side are equal)
let the angles be x each.
Now by angle sum property
∠A+∠B+∠C=180°
⇒x+x+80°=180°
⇒2x=180°−80°
⇒2x=100
x=100/2
⇒x=50°
∴∠A=50°
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