in triangleABC if a=8cm,b=15cm,c=17cm then the length of median(mc) is
Answers
Answer- hope it hepls you:)
Step-by-step explanation:
We know that medians divide the triangle in
six equal areas.
Let ABC is a triangle ,in which medians AM=9
cm. BN=12 cm. and CP=15 cm.
Let medians meet at O.
OM=1/3 of AM =1/3×9cm= 3 cm.
ON=1/3 ×12 cm. = 4cm.
OP=1/3 ×15 cm.= 5 cm.
Produce AM upto S such MS = OM=3 cm.
join S to C and B.
In triangle COS , OS=OM+MS=3+3= 6 cm.
OC=2/3 ofCP=2/3 ×15 cm.= 10cm.
CS=OB= 2/3 ofBN =2/3 ×12 cm.= 8 cm.
s =(6+8+10)/2=12 cm.
Area of triangle COS =[s(s-a)(s-b)(s-c)]^1/2
=[12(12–6)(12–8)(12–10)]^1/2
=[12×6×4×2]^1/2
=24 cm^2.
Area of triangle COM = 1/2 ×Area of triangle COS.
Area of triangle COM =1/2 ×24 cm^2 =12 cm^2.
Area of triangle ABC = 6 ×Area of triangle COM
= 6 × 12 cm ^2
= 72 cm^2. Answer
Answer:
perpendicular (AB)= 8cm
base(BC) =15cm
hypotenuse(AC)=17cm
sinA= P/H =8/17
cosA = B/H =15/17
tanA =P/B= 8/15