Math, asked by msrider, 8 months ago

In triangleABC, right angled at B,AB=21cm, AC-BC =9cm. Find the value of sinC - Cos C

Answers

Answered by sangeeta144178

8

Answer:

In ∆ABC, B = 90°. AB=21cm AC=9+BC by using Pythagoras theorem,. BC=20cm,. AC= 29cm. sin C = BC/AC =20/29. cos C = AB/AC=21/29 sin C - cos C = 20/29-21/29 = -1/29

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