Math, asked by pallavithakuria1, 1 year ago

In triangleABC right angled atB if AB=40cm BC=9cm and AC=41cm find the values of sinC cotC cosA and cotA

Answers

Answered by silentkiller13
3

Use the following formulas

SinC=opposite side /Hypotenuse

=AB/AC

=40/41

Answered by pratimabilung00
1

Step-by-step explanation:

sin C= AB/AC = 40/41

cot C= AB/AC = 9/40

cot A= AB/AC = 40/41

cot A= AB/BC = 40/9

Attachments:
Similar questions