In triangleABC right angled atB if AB=40cm BC=9cm and AC=41cm find the values of sinC cotC cosA and cotA
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Answered by
3
Use the following formulas
SinC=opposite side /Hypotenuse
=AB/AC
=40/41
Answered by
1
Step-by-step explanation:
sin C= AB/AC = 40/41
cot C= AB/AC = 9/40
cot A= AB/AC = 40/41
cot A= AB/BC = 40/9
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