in triangleABC,righttriangled at C, angleA is equal to angle B, find the value of SinASinB+CosACosB
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Answer:
1
Step-by-step explanation:
GIVEN
Angle C = 90
and Angle A = B. ...(1)
cos(A - B) = sinAsinB+cosAcosB
from equation 1st
Angle A = B
cos(A-A) = cos0 = 1
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