Question

In triangleABC, the perpendicular AD from A to the bisector BD of the angle ABC meets the base BC
produced if necessary) at E. Prove that AD = DE.​

Answer 1

Answer:

Read it carefully

Step-by-step explanation:

∠ABD = ∠EBD = m(∠B) / 2

∠ADB = ∠EDB = 90°

Hence the two triangle are similar.

Since, DB is a common side between the two triangles, other sides are also equal.      

so  AD = DE.

Hope it will help u friend!