In Triangles, ABC and DEF, AB=FD and angleA=angleD The two triangles will be congruent by SAS postulate if:BC=EF, AC=DE, AC=EF, BC=DE.
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For triangle to be congruent by SAS axiom two of the sides and the included angle of the triangles must be equal.
Given AB=DF and ∠A=∠D
No for △ABC≅△DFE by SAS axiom we need AC=DE
So option B is correct.
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