Question

In triangles ABC and PQR, AB =PQ,AC =PR and altitude AM and altitude PNare equal. Show that triangle ABC is congruent to triangle PQR .

Answer 1

since altitude is the line which make right angle so

$< n = 90 \\ < m = 90$

then

in tri amc and tri pnr

$< m = < n$

each 90 degree

am=pn. given

ac=pr. given

so

$tri \: amc \: is \: congurent \: to \: tri \: anr$

then

double is or multiply by 2

tri abc. is congruent to tri pqr

bcoz altitude divide a tri in 2 congruent tri

Answer 2

Answer:

Step-by-step explanation:In triangle ABM and triangle PQN;

Angle AMB=Angle PNQ=90 [Since altitudes are perpendiculars]

AB=PQ [Since given]

AM=PN [Since given]

By RHS Congruency;

Triangle ABM is congruent to Triangle PQN

Similarly, Triangle ACM is congruent to Triangle PRN

Therefore, ABM + ACM is conguent to PQN +PRN

= ABC is conguent to PQR