Question

In triangles PQR, right angled at
Q, PQ = 3cm and PR = 6cm.
Determine angle QPR.​

Answer 1

Answer:

in triangle PQR,

PR is hypotenuse and PQ is adjacent

cos theta= adjacent/hypotenuse =PQ/PR

cos theta =3/6=1/2

cos theta=1/2

therefore theta =60°(cos 60°=1/2)

therefore, angle QPR=60°

Answer 2

Answer:

Given: PQ = 3cm

PR = 6cm

$Therefore,\frac{PQ}{PR} = sin R \\ \\ </p><p>sin R = \frac{3}{6} = \frac{1}{2} \\ \\ \angle {PRQ}=30°</p><p>\\ \\ \angle{QPR} = 60°$