Question

In trianle ABC pq is parallel to bc and ap=3x-19,pb=x-5,aq=x+3,qc=3cm find x value anybody solve it fastly

Answer 1

Step-by-step explanation:

given triangle abc , bc parallel pq

accocrfing to basic proportionality theorem,

ap/bp= aq/qc

3x-19/x-5 = x+3/3

9x-57=(x-5)(x-3)

17x-57= x^2+15

17x-72= x^2

x^2-17x+72=0

now ,

x= -9 or x = -8

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Answer 2

Step-by-step explanation:

answer

is

x

=

8

,

9

x=8,9

x=8,9