Question

in trianlgle ABC and DEF ,AngleA=angleE = 50 AB/ED=AC/EFand anlge F= 65 show that AB=AC​

Answer 1

Answer:

In △ABC and △DEF,

∠A=∠E=40

∘

ED

AB

=

EF

AC

Thus, △ABC∼△DEF (SAS rule)

or ∠C=∠F=65

∘

Now, In △ABC,

∠A+∠B+∠C=180 (Sum of angles of triangle)

40+65+∠B=180

∠B=180−105

∠B=75

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