Question

in trisngle ABC,AB=6squareroot3,AC=12cm,BC=6cm.find measure angle of A

Answer 1

Answer:

AB=6√3CM

AC=12CM

BC=6CM

AC²=BC²+AB²

12=√{6²+(6√3)²}

12=√[6*6+6√3*6√3]

12=√[6*6(1+√3*√3)]

12=6√1+3

12=6√4

12=6*2

12=12

By converse of Pythagoras theorem

ABC is a right triangle right angled at B

TanA=BC/AB

=6/6√3

=1/√3

A=30°