Question

in tru4ABC, DE parallel BC if AD = 2cm , DB =5cm and AE = 4cm find AC​

Answer 1

when DE//BC,

AD/DB = AE/EC

2/5 = 4/EC

THEREFORE,

EC = 20/2

= 10 cm

so, AC = AE + EC

= 4 + 10 = 14 cm

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Answer 2

Answer:

GIVEN:

∆ABC,where DE//BC

• ACCORDING TO BASIC PROPORTIONALLY THEROM

AD/DB=AE/EC

2/5=4/EC {Cross multiplication}

2EC=20

EC=20/2

EC=10

• NOW AC=AE+EC
• AC=4+10
• AC=14CM