In two alloys, the ratio of iron and copper is 4 : 3 and 6 : 1, respectively. If 14 kg of the first alloy and 42 kg of the second alloy is mixed together to form a new alloy, then what will be the ratio of iron to copper in the new alloy ?
Answers
Answer:
Explanation:
Proportion of iron in first alloy = 4/7 (total alloy = 4+3 =7 ) Proportion of iron in second alloy 6/7 (total alloy = 6+1=7)
Weight of first alloy = 14 kg
= 4×2 / 7×2
= 8/14
Weight of second alloy= 42 kg
= 6×6 / 7×6
= 36/42
Thus, the total iron in (14+42) kg ore
= 36+ 8
= 44 kg
Quantity of copper = (14+42)- 44
= 12 kg
Ratio of copper: iron
= 12:44
= 3:11
Answer:
Explanation:
Proportion of iron in first alloy = 4/7 (total alloy = 4+3 =7 ) Proportion of iron in second alloy 6/7 (total alloy = 6+1=7)
Weight of first alloy = 14 kg
= 4×2 / 7×2
= 8/14
Weight of second alloy= 42 kg
= 6×6 / 7×6
= 36/42
Thus, the total iron in (14+42) kg ore
= 36+ 8
= 44 kg
Quantity of copper = (14+42)- 44
= 12 kg
Ratio of copper: iron
= 12:44
= 3:11