Question

In two coencentric circles Prove that all chords of Outer circle which touch the inner circle are of equal length..

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Answer 1

Hey there!

★ Construction: JOIN OP & OQ

★ Solution:

Since, Tangent is perpendicular to the Radius at point of Contact
So,
OP ⊥ AB & OQ ⊥ CD

Also, OP = OQ [ Radii of same circle ]

Since, Chords equidistant from centre of circle are equal in length
Therefore, AB = CD

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