Question

in two concentric circles prove that a chord of larger circle which is danger to the smaller circle is bisected at the point of contact​

Answer 1

Answer:

To prove: AP = BP. Construction: Join OP. Proof: AB is a tangent to the smaller circle at the point P and OP is the radius through P. ... But, the perpendicular drawn from the centre of a circle to a chord bisects the chord.

Answer 2

Answer:

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