In two concentric circles, prove that all chords of the outer circle, which touch the inner circle are of equal length (with figure)...!!
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61
Solution:
Let AB and CD be two chords of the circle which touch the inner circle at M and N respectively.
To prove:
AB = CD
Explanation:
Since AB and CD are tangents
to the smaller circle .
OM = ON
/* radius of the smaller circle */
AB and CD are the two chords
of the larger circle such that
they are equidistant from the centre.
Hence ,
AB = CD
••••
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Answered by
38
Here is ur answer. Pls do vote
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