in two days a b and c together can finish 1/2 of a work and in another 2 days b and c together can finish 3/10 par of the work. then a alone can complete the whole work in
Answers
b+c = 3/10
therefore,
a + 3/10 = 1/2
a = 1/2 - 3/10
a = 1/5
so a can finish 1/5th of the given work in 2 days.
a alone can complete the whole work in 10 days
Step-by-step explanation:
in two days a b and c together can finish 1/2 of a work
=> a + b + c together 2 day work = 1/2
=> a + b + c together 1 day work = 1/4
in another 2 days b and c together can finish 3/10 part of the work
=> b + c together 2 day work = 3/10
=> b + c together 1 day work = 3/20
a's 1 day work = a + b + c together 1 day work - b + c together 1 day work
=> a's 1 day work = 1/4 - 3/20 = (5 - 3)/20 = 2/20 = 1/10
=> a alone can complete the whole work in 10 days
Remaining Work = 1 - 1/2 - 3/10 = (10 - 5 - 3)/10 = 2/10
and remaining work in 2 days
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